SELECT 2 BETWEEN 1 AND 3, 1 BETWEEN 2 AND 3; // 1, 0
SELECT *, COUNT(video_id) FROM video_thumb GROUP BY video_id HAVING ( COUNT(video_id) > 1 );
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME IN ('myphone') AND TABLE_SCHEMA='mydb'; // output: mytable
SELECT FIND_IN_SET('b','a,b,c,d'); //2
